Given: Show #"First equation":##x+y=4# #"Second equation:"##x-y=-6# Find the x- and y-intercepts for each equation. Graph the points for each line separately, and draw a straight line through the points of both lines. The point at which they intersect is the solution to the system. The x-intercept is the value of #x# when #y=0#. The y-intercept is the value of #y# when #x=0#. First equation x-intercept: Substitute #0# for #y#. #x+0=4# #x=4# The x-intercept is #(4,0)#. y-intercept: Substitute #0# for #x#. #0+y=4# #y=4# The y-intercept is #(0,4)#. Plot the points and draw a straight line through them. graph{x+y=4 [-10, 10, -5, 5]} Second equation x-intercept: Substitute #0# for #y#. x-0=-6# #x=-6# The x-intercept is #(-6,0)#. y-intercept: Substitute #0# for #x#. #0-y=-6# #-y=-6# Multiply both sides by #-1#. This will reverse the signs. #y=6# The y-intercept is #(0,6)#. Plot the points on the same graph and draw a straight line through them. The point of intersection is #(4,5)#. This is the solution to the given system of equations. graph{(x+y-4)(x-y+6)=0 [-10, 10, -5, 5]}
How do you solve a linear system by graphing?To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect. The two lines intersect in (-3, -4) which is the solution to this system of equations.
How do you solve system of linear equations?How do I solve systems of linear equations by substitution?. Isolate one of the two variables in one of the equations.. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ... . Solve the linear equation for the remaining variable.. How do you do graphing linear equations?To graph an equation using the slope and y-intercept, 1) Write the equation in the form y = mx + b to find the slope m and the y-intercept (0, b). 2) Next, plot the y-intercept. 3) From the y-intercept, move up or down and left or right, depending on whether the slope is positive or negative.
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