Addition and subtraction word problems with regrouping

Addition and subtraction word problems with regrouping

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How to use a mixed word problems for Grade 4 PDF?

These differentiated Addition and Subtraction worksheets allow children to solve word problems and challenges their understanding of the topic.

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How to use a mixed word problems for Grade 4 PDF?

These differentiated Addition and Subtraction worksheets allow children to solve word problems and challenges their understanding of the topic.

It is ideal to use in your Maths lessons on addition and subtraction as you can use the seven different word problems included to test children's knowledge.

All of our resources are teacher-made, including this mixed word problems for Grade 4 PDF. Meaning that regardless of whether you are home or in the classroom, a teacher or a parent, you can be confident that all the knowledge you pass onto your students is accurate, relevant and up to date.

Plus, an answer sheet is included to make your life easier! If you would like even more addition and subtraction word problems, why not try these Challenge Cards?

What is the subtraction rule?

  • Subtraction is the step of taking a number or amount away from another. 
  • It can be done by counting backwards.
  • For example: 2 - 1 = 1 or 10 - 5 = 5.
  • Subtracting can also be called to 'take away' or 'minus'.

If you are looking for more mixed word problems for grade 4 like this PDF, you can take a look at some of our hand-picked suggestions below:

  • Differentiated Addition and Subtraction Word Problems Activity Sheets
  • Two-Step Maths Word Problems Differentiated Worksheets
  • Multi-Step Word Problems Worksheet

If you have been inspired by our mixed word problems for Grade 4 PDF and would like to make your own, have a look at our Twinkl Create App.

What are addition and subtraction word problems?

In Maths, a word problem is an exercise where background information is provided in the form of text.

Word problems are a great way to support your teaching of this topic as they relate to specific scenarios to help them apply their understanding in a real-life context. 

Word problems can also help children to recognise the types of vocabulary that are used in maths and give them the confidence to use it themselves.

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Word problems involving addition and subtraction are discussed here step by step.


There are no magic rules to make problem solving easy, but a systematic approach can help to the problems easily. 

Word problems based on addition are broadly of two types:

(a) When objects of two or more collections are put together.

For example:

Amy has 20 lemon sweets and 14 orange sweets. What is the total number of sweets Amy has?

(b) When an increase in number takes place.

For example:

Victor has 14 stamps. His friend gave him 23 stamps. How many stamps does Victor have in all?

The key words used in problems involving addition are:

sum; total; in all; all together.

Word problems based on subtraction are of several types:

(a) Partitioning : Take away, remove, given away.

(b) Reducing : Find out how much has been given away or how much remains.

(c) Comparison : More than / less than.

(d) Inverse of addition : How much more to be added. The key words to look out for in a problem sum involving subtraction are:
take away; how many more ; how many less ; how many left ; greater ; smaller.

1. The girls had 3 weeks to sell tickets for their play. In the first week, they sold 75 tickets. In the second week they sold 108 tickets and in the third week they sold 210 tickets. How may tickets did they sell in all?

Tickets sold in the first week = 75

Tickets sold in the second week = 108

Tickets sold in the third week = 210

Total number of tickets sold = 75 + 108 + 210 = 393

Answer: 393 tickets were sold in all.

2. Mr. Bose spent $450 for petrol on Wednesday. He spent $125 more than that on Thursday. How much did he spend on petrol on those two days.

This problem has to be solved in two steps.

Step 1: Money spent for petrol on Thursday

450 + 125 = $575

Step 2: Money spent for petrol on both days

450 + 575 = $1025

Examples on word problems on addition and subtraction:

1. What is the sum of 4373, 4191 and 3127?

Solution:

The numbers are arranged in columns and added.

Addition and subtraction word problems with regrouping

(i) Ones are added: 3 + 1 + 7 = 11 = 1 Ten + 1 one

(ii) Tens are added: 1 + 7 + 9 + 2 = 19 tens

= 1 hundred + 9 ten

(iii) Hundreds are added: 1 + 3 + 1 + 1 = 6 Hundred

(iv) Thousands are added: 4 + 4 + 3 = 11 Thousand

Therefore, sum =11,691

2. What is the difference of 3867 and 1298?

Solution:

The numbers are arranged in columns and subtracted:

Addition and subtraction word problems with regrouping

(i) Ones are subtracted: 7 < 8

1 is borrowed from 6 ten. So, 1 T or 10 + 7 = 17,

17 - 8 = 9

(ii) Tens are subtracted; 5 T < 9 T,

So, 1 H or 10 T is borrowed from 8 H, 1 H = 10 T + 5 T = 15T

15T - 9T = 6

(iii) Hundreds are subtracted 7 H – 2 H = 5 H

(iv) Thousands are subtracted 3 Th – 1 Th = 2 Th

Therefore, difference = 2569

3. Subtract 4358 from the sum of 5632 and 1324.

Solution:

Sum of 5632 and 1324

Addition and subtraction word problems with regrouping

Difference of 6956 and 4358

Addition and subtraction word problems with regrouping

(i) 6 < 8, 1 T or 10 ones are borrowed

1 T or 10+ 6 =16, 16 - 8 = 8

(ii) 4 T < 5 T, 1 H or 10 T is borrowed

10 T + 4 T = 14 T, 14 T – 5 T = 9 T

(iii) 8 H – 3 H = 5 H

(iv) 6 Th – 4 Th = 2 Th

Therefore, 2598 is the answer.

4. Find the number, which is

(i) 1240 greater than 3267.

(ii) 1353 smaller than 5292.

Solution:

(i) The number is 1240 more than 3267

Addition and subtraction word problems with regrouping

Therefore, the number = 3267 + 1240 or = 4507

(ii) The number is 1353 less than 5292

Addition and subtraction word problems with regrouping

Therefore, the number

= 5292 – 1353 or

= 3939

5. The population of a town is 16732. If there are 9569 males then find the number of females in the town.

Solution:

Population of the town

Number of males

Therefore, number of females


=   1 6 7 3 2
=   - 9 5 6 9
=     7 1 6 3

6. In a factory there are 35,675 workers. 10,750 workers come in the first shift, 12,650 workers in the second shift and the rest come in the third shift. How many workers come in the third shift?

Solution:

Number of workers coming in the first and second shift

Addition and subtraction word problems with regrouping

= 10750 + 12650 = 23400

Addition and subtraction word problems with regrouping


Therefore, number of workers coming in the third shift = 35675 - 23400 = 12275

Related Concept

Addition

Word Problems on Addition

Subtraction

Check for Subtraction and Addition

Word Problems Involving Addition and Subtraction

Estimating Sums and Differences

Find the Missing Digits

Multiplication

Multiply a Number by a 2-Digit Number

Multiplication of a Number by a 3-Digit Number

Multiply a Number

Estimating Products

Word Problems on Multiplication

Multiplication and Division

Terms Used in Division

Division of Two-Digit by a One-Digit Numbers

Division of Four-Digit by a One-Digit Numbers

Division by 10 and 100 and 1000

Dividing Numbers

Estimating the Quotient

Division by Two-Digit Numbers

Word Problems on Division

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